1.4 Activity: Solving Algebraic Equations-Making Connections to Balance Act

This activity will help us further our understanding of the role/meaning of equality sign by utilizing the balance scale with expressions to solve an algebraic equation and revisit the meaning of “solution of an equation.”

Part A

1) Go to the following link: Pan Balance – Expressions (Open in new window)

Follow the instructions to get familiar with the app, then complete the exploration. Provide your answers to the exploration questions #2-6 below :

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Try another equation and solve it using this app. Write your equation and solution below and explain how you used the app to solve it .

 

 

 

 

Part B

Review the following model (from Mathematics for Elementary Teachers by Sybilla Beckman), showing how to solve equations algebraically and using a pan balance.  Consider the following questions:

(1) What did you learn about solving an equation?

(2) What similarities and differences do you see with this activity and the previous scale activities?

(3) How might an elementary school teacher use the Pan Balance to explain the process of solving an equation algebraically?

With a Pan Balance and Equations

Pan balance on the left with 4 X boxes, 2 boxes, and 1 X box. On the right with 5 boxes, 3 X boxes, and 3 boxes.

[latex]4x+2+x=5+3x+3[/latex]

Change to equivalent expressions.

Pan balance reorganized to on the left, 5 X boxes and 2 boxes. On the right, 3 X boxes and 8 boxes.

[latex]\begin{align*} 5x+2 &= 3x+8 \\ -2 &= -2 \\ \end{align*}[/latex]

Take 2 away from both sides.

Pan balance take 2 boxes away from both sides. On the left, 5 X boxes and on the right, 3 X boxes and 6 boxes.

[latex]\begin{align*} 5x &= 3x+6 \\ -3x &= -3x \\ \end{align*}[/latex]

Take 3x away from both sides.

Pan balance, take 3 X boxes away from both sides. On left, 2 X boxes and on the right, 6 boxes.

[latex]2x=6[/latex]

Divide both sides by 2.

Take half of each side (i.e., divide each side by half). Pan balance on the left is 1 X box and on the right 3 boxes.

[latex]x=3[/latex]

For extra explanation and examples watch the following videos:

Part C

Solve [latex]5x + 1 = 2x + 7[/latex] in two ways, (1) with equations and (2) with pictures of a pan balance. Relate the two methods with common explanations as done in Part B.


With equations:

[latex]5x + 1 = 2x + 7[/latex]

 

 

 

 

 

 

 

 

 


With a pan balance:

Pan balance showing on the left 5 x boxes and 1 box and on the right, 2 x boxes and 7 boxes.

Illustration of an empty pan balance scale

Illustration of an empty pan balance scale

Illustration of an empty pan balance scale

 

Part D

Write an equation involving variable x. Solve your equation in two ways: (1) with equations and (2) with the pictures of a pan balance. Relate the two methods with common explanations as done in Part B.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Chapter 1: Extra Exercises with more advanced equations, but first review corresponding algebraic properties as needed. (click on the triangle/arrow to expand)

1. Maria was given the following problem to solve: [latex]\frac{4x}{x+2}=3-\frac{8}{x+2}[/latex]

Her work is below. Explain what she did for each step and why her final answer is not valid.

[latex]4x = 3(x + 2) - 8[/latex]

[latex]4x = 3x + 6 - 8[/latex]

[latex]4x = 3x - 2[/latex]

The solution is [latex]x = -2[/latex]

 

 

 

 

 

 

 

 

 

 

 

2. Yihang was given the following problem to solve: [latex](\frac{1}{3}x-2)^{2}=\sqrt{4-x}[/latex]

His work is below. Explain what he did for each step and why his final answer is not valid.

[latex](\frac{1}{3}x-2)^{2}=4-x[/latex]

[latex]\frac{1}{9}x^{2}-\frac{4}{3}x+4=4-x[/latex]

[latex]x^2-12x+36=36-9x[/latex]

[latex]x^2-3x=0[/latex]

[latex]x(x-3)=0[/latex]

The solutions are [latex]x = 0[/latex] and [latex]x = 3[/latex].

 

 

 

 

 

 

 

 

 

 

 

 

 

 

3. For parts (a) – (c) an equation is given along with three attempts by various students to write an equivalent equation. For each student in each part, determine if their equation is equivalent to the original equation or not. Explain why or why not.

 

a) Original equation: [latex](x+3)^2=4x^2-36[/latex]

Alice: [latex]x+3=2x-6[/latex]

 

 

 

 

Bubba: [latex]x^2+9=4x^2-36[/latex]

 

 

 

 

Dalia: [latex]x^2=4x^2-39[/latex]

 

 

 

b) Original equation: [latex]x+\sqrt{x^2+9}=4[/latex]

Bubba: [latex]x^2+(x^2+9)=16[/latex]

 

 

 

 

Dalia: [latex]x+(x+3)=4[/latex]

 

 

c) Original equation: [latex]\frac{3x}{x+4}=2x-5[/latex]

Bubba: [latex]\frac{3}{4}=2x-5[/latex]

 

 

 

 

Dalia: [latex]3x=2x-5(x+4)[/latex]

 

 

 

 

 

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